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8x^2+46x+30=0
a = 8; b = 46; c = +30;
Δ = b2-4ac
Δ = 462-4·8·30
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-34}{2*8}=\frac{-80}{16} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+34}{2*8}=\frac{-12}{16} =-3/4 $
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